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std::map<std::string, std::string> a; std::string m = 2; //编译失败 a["hello"] = 1; //编译成功 为什么呢
 | 1 Orchestraa Feb 11, 2025 m 是构造，a 是赋值 |
 | 2 Shatyuka Feb 11, 2025 构造函数不要 char ，赋值可以。 试试： ```cpp std::string n; n = 3; ``` |
 | 3 yanqiyu Feb 11, 2025 构造函数没有接一个 char 的构造[1]，但是有接一个 char 的 assign[2] [1]: https://en.cppreference.com/w/cpp/string/basic_string/basic_string [2]: https://en.cppreference.com/w/cpp/string/basic_string/operator%3D |
 | 4 Opportunity Feb 11, 2025 前一个是拷贝构造，后一个是赋值。 ``` std::string m; m = 2; ``` 也可以的。https://en.cppreference.com/w/cpp/string/basic_string/operator%3D 看示例 6 |
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