Django 中模板的 if 条件这样为什么出错了? - V2EX
V2EX = way to explore
V2EX 是一个关于分享和探索的地方
Sign Up Now
For Existing Member  Sign In
推荐学习书目
Learn Python the Hard Way
Python Sites
PyPI - Python Package Index
http://diveintopython.org/toc/index.html
Pocoo
值得关注的项目
PyPy
Celery
Jinja2
Read the Docs
gevent
pyenv
virtualenv
Stackless Python
Beautiful Soup
结巴中文分词
Green Unicorn
Sentry
Shovel
Pyflakes
pytest
Python 编程
pep8 Checker
Styles
PEP 8
Google Python Style Guide
Code Style from The Hitchhiker's Guide
cheyo

Django 中模板的 if 条件这样为什么出错了?

  •  
  •   cheyo Oct 30, 2014 4568 views
    This topic created in 4199 days ago, the information mentioned may be changed or developed.
    {% if 1==house.status %}
    <span class="label label-success">
    {% elif 2==house.status %
    <span class="label label-primary">
    {% elif 3==house.status %}
    <span class="label label-info">
    {% elif 4==house.status %}
    <span class="label label-default">
    {% else %}
    <span class="label label-danger">
    {% endif %}
    {{ house.get_status_display }}</span>

    错误信息:
    TemplateSyntaxError at /project/19607/
    Could not parse the remainder: '==house.status' from '1==house.status'

    谢谢
    10 replies    2014-10-31 17:24:27 +08:00
    stillwater
        1
    stillwater  
       Oct 30, 2014
    用ifequal?
    virusdefender
        2
    virusdefender  
       Oct 30, 2014   1
    {% ifequal a "111" %}{% endifequal %}判断相等
    ericls
        3
    ericls  
       Oct 30, 2014 via Android   1
    if house.status == 1应该可以
    注意必须有空格
    cheyo
        4
    cheyo  
    OP
       Oct 30, 2014
    @ericls 果然加一个空格就行了
    @stillwater
    @virusdefender 用ifequal也行

    谢谢
    rcmerci
        5
    rcmerci  
       Oct 30, 2014
    模板里空格挺严格的
    mornlight
        6
    mornlight  
       Oct 30, 2014
    要有空格,如果你用Pycharm的话应该会提示你
    taobeier
        7
    taobeier  
       Oct 31, 2014
    不太习惯的话, 就用个IDE会稍微好点。
    tuteng
        8
    tuteng  
       Oct 31, 2014
    mark
    gevin
        9
    gevin  
       Oct 31, 2014
    如果house.status的类型是str,你的代码那个就成了:
    {% if 1=='1' %}

    这种情况下就会报错

    需要保持 '==' 两边值得类型一致
    nooper
        10
    nooper  
       Oct 31, 2014
    Try to remove the complex in the if cases.Just judge by integer , what if the status change , that's should not be hard code in the template. and you'd better add the logic into the views. or templatetags.
    About     Help     Advertise     Blog     API     FAQ     Solana     2816 Online   Highest 6679       Select Language
    创意工作者们的社区
    World is powered by solitude
    VERSION: 3.9.8.5 67ms UTC 15:30 PVG 23:30 LAX 08:30 JFK 11:30
    Do have faith in what you're doing.
    ubao msn snddm index pchome yahoo rakuten mypaper meadowduck bidyahoo youbao zxmzxm asda bnvcg cvbfg dfscv mmhjk xxddc yybgb zznbn ccubao uaitu acv GXCV ET GDG YH FG BCVB FJFH CBRE CBC GDG ET54 WRWR RWER WREW WRWER RWER SDG EW SF DSFSF fbbs ubao fhd dfg ewr dg df ewwr ewwr et ruyut utut dfg fgd gdfgt etg dfgt dfgd ert4 gd fgg wr 235 wer3 we vsdf sdf gdf ert xcv sdf rwer hfd dfg cvb rwf afb dfh jgh bmn lgh rty gfds cxv xcv xcs vdas fdf fgd cv sdf tert sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf shasha9178 shasha9178 shasha9178 shasha9178 shasha9178 liflif2 liflif2 liflif2 liflif2 liflif2 liblib3 liblib3 liblib3 liblib3 liblib3 zhazha444 zhazha444 zhazha444 zhazha444 zhazha444 dende5 dende denden denden2 denden21 fenfen9 fenf619 fen619 fenfe9 fe619 sdf sdf sdf sdf sdf zhazh90 zhazh0 zhaa50 zha90 zh590 zho zhoz zhozh zhozho zhozho2 lislis lls95 lili95 lils5 liss9 sdf0ty987 sdft876 sdft9876 sdf09876 sd0t9876 sdf0ty98 sdf0976 sdf0ty986 sdf0ty96 sdf0t76 sdf0876 df0ty98 sf0t876 sd0ty76 sdy76 sdf76 sdf0t76 sdf0ty9 sdf0ty98 sdf0ty987 sdf0ty98 sdf6676 sdf876 sd876 sd876 sdf6 sdf6 sdf9876 sdf0t sdf06 sdf0ty9776 sdf0ty9776 sdf0ty76 sdf8876 sdf0t sd6 sdf06 s688876 sd688 sdf86