请教 PY 的两个循环结束添加元素到集合,结果为什么不一样? - V2EX
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scylla

请教 PY 的两个循环结束添加元素到集合,结果为什么不一样?

  •  
  •   scylla Jan 24, 2015 3555 views
    This topic created in 4114 days ago, the information mentioned may be changed or developed.
    代码要实现的功能是把文本文件里的IP地址匹配出来,并把IP添加到集合里。

    代码1:

    <script src=".py">

    re_ip = re.compile('[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}')
    ip_list = []
    with open(path, 'r') as f:
    for line in f:
    ips = re_ip.findall(line)
    ip_list.append(str(x) for x in ips)

    </script>

    代码1里,集合的结果是这种对象 <generator object <genexpr> at 0x10417ffa0> .... 其实我想要的是IP地址。


    代码2:

    <script src=".py">

    re_ip = re.compile('[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}')
    ip_list = []
    with open(path, 'r') as f:
    for line in f:
    ips = re_ip.findall(line)
    for x in ips:
    ip_list.append(x)

    </script>

    代码2的集合里,结果才是IP地址。

    为什么会这样?请不吝赐教,谢谢。
    6 replies    2015-01-26 01:45:40 +08:00
    SakuraSa
        1
    SakuraSa  
       Jan 24, 2015
    因为 ip_list.append(str(x) for x in ips) 中的 (str(x) for x in ips) 就是一个 generator 呀
    我觉得你可能是想这样 ip_list.extend(str(x) for x in ips)
    SakuraSa
        2
    SakuraSa  
       Jan 24, 2015
    另外 findall 的结果就是一个字符串的数组
    可以直接 ip_list.append(re_ip.findall(line))
    SakuraSa
        3
    SakuraSa  
       Jan 24, 2015
    错了,是 ip_list.extend(re_ip.findall(line))
    huangyanan
        4
    huangyanan  
       Jan 24, 2015
    extend for the first sample
    scylla
        5
    scylla  
    OP
       Jan 24, 2015
    @SakuraSa

    谢谢。 (str(x) for x in ips) 会被解释成一个 generator?怪不得。 ip_list.extend(re_ip.findall(line)) 是可用的。

    话说怎么粘代码高亮?用markdown 的’‘’python 和<script src=".py"> 标签都不行。
    ryd994
        6
    ryd994  
       Jan 26, 2015 via Android
    写程序时不看文档么?出了问题还不看?
    既然看见存了genenrator,那就看看哪个list方法会取出所有元素而不是直接存入集合啊!
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