请问 php 中怎样合并二维数组相同的 key? - V2EX
V2EX = way to explore
V2EX 是一个关于分享和探索的地方
Sign Up Now
For Existing Member  Sign In
jinganchuqi
V2EX    PHP

请问 php 中怎样合并二维数组相同的 key?

  •  1
     
  •   jinganchuqi Apr 2, 2015 5381 views
    This topic created in 4046 days ago, the information mentioned may be changed or developed.

    请问怎样合并period相同,并且price相同的数组?

    合并前
    $arr = array(
    array("id"=>,'num'=>5,'period'=>3,'price'=>5),
    array("id"=>2,'num'=>10,'period'=>3,'price'=>5),
    array("id"=>3,'num'=>15,'period'=>9,'price'=>20),
    );

    合并后
    $arr = array(
    array('num'=>15,'period'=>3,'price'=>5),
    array('num'=>15,'period'=>9,'price'=>20),
    );
    第一次发贴,多多见谅哈!

    20 replies    2015-04-03 17:22:41 +08:00
    kmvan
        1
    kmvan  
       Apr 2, 2015   1
    <?php

    $old = [
    ["id"=>1,'num'=>5,'period'=>3,'price'=>5],
    ["id"=>2,'num'=>10,'period'=>3,'price'=>5],
    ["id"=>3,'num'=>15,'period'=>9,'price'=>20]
    ];

    $new = [];
    foreach($old as $k => $v){
    if(isset($new[$v['period']])){
    $new[$v['period']]['num'] += $v['num'];
    }else{
    unset($v['id']);
    $new[$v['period']] = $v;
    }
    }

    var_dump($new);


    ?>
    输出耗时:0.00074601173400879ms
    tuoxie007
        2
    tuoxie007  
       Apr 2, 2015
    就三条数据,测耗时意义不大吧。。。
    tuoxie007
        3
    tuoxie007  
       Apr 2, 2015
    @kmvan 就三条数据,测耗时意义不大吧。。。
    kmvan
        4
    kmvan  
       Apr 2, 2015
    @tuoxie007 就三条数据,测耗时意义不大吧。。。
    你一定是妒忌我和我的头像
    jinganchuqi
        5
    jinganchuqi  
    OP
       Apr 2, 2015
    @kmvan 谢谢,但是我要的是 合并period相同,并且price也相同的数组呀,您还能给我说说其他方法吗?
    kmvan
        6
    kmvan  
       Apr 2, 2015
    @jinganchuqi 我要的是 合并period相同,并且price也相同的数组呀,您还能给我说说其他方法吗?
    你的结果 price 也没有相同。
    kmvan
        7
    kmvan  
       Apr 2, 2015   1
    <?php

    $old = [
    ["id"=>1,'num'=>5,'period'=>3,'price'=>5],
    ["id"=>2,'num'=>10,'period'=>3,'price'=>5],
    ["id"=>3,'num'=>15,'period'=>9,'price'=>20]
    ];

    $new = [];
    foreach($old as $k => $v){
    if(isset($new[$v['period']])){
    $new[$v['period'] . $v['price']]['num'] += $v['num'];
    }else{
    unset($v['id']);
    $new[$v['period'] . $v['price']] = $v;
    }
    }

    var_dump($new);

    //这样就ok了啊。isset的效率略高。
    jinganchuqi
        8
    jinganchuqi  
    OP
       Apr 2, 2015
    @kmvan 好吧,对不起,是我表达不清楚 。 我的意思是 以period 和 price 都相同 来作为合并的条件。
    jinganchuqi
        9
    jinganchuqi  
    OP
       Apr 2, 2015
    @kmvan 十分感谢您啦!!!!
    l1905
        10
    l1905  
       Apr 2, 2015   1
    <?php
    $arr = array(
    array("id"=>1,'num'=>5,'period'=>3,'price'=>5),
    array("id"=>2,'num'=>10,'period'=>3,'price'=>5),
    array("id"=>3,'num'=>15,'period'=>9,'price'=>20),
    );
    $result = array();
    $check = array();
    foreach ($arr as $k => $data) {
    $ser = serialize(array('period'=>$data['period'], 'price'=>$data['price']));
    if(!in_array($ser, $check)) {
    array_push($check, $ser);
    $result[$ser] = array('num'=>$data['num'],'period'=>$data['period'], 'price'=>$data['price']);
    } else {
    $result[$ser]['num'] += $data['num'];
    }
    }
    var_dump(array_values($result));

    ?>
    实现效率不肿么高。。。
    kn007
        11
    kn007  
       Apr 3, 2015
    学习一下
    mhycy
        12
    mhycy  
       Apr 3, 2015
    mhycy
        13
    mhycy  
       Apr 3, 2015
    @kmvan 之前那个写法不怕period和price连在一起出问题么?都是数字。。。
    kmvan
        14
    kmvan  
       Apr 3, 2015 via Android
    @mhycy 之前那个写法不怕period和price连在一起出问题么?都是数字。。。
    显然不会。而且最高效,跑10w次1ms都不用
    Sinute
        15
    Sinute  
       Apr 3, 2015
    https://gist.github.com/Sinute/f67544f3bbcabe8d126c

    @kmvan
    试试 period=11, price=12和period=1, price=112
    mhycy
        16
    mhycy  
       Apr 3, 2015
    mhycy
        17
    mhycy  
       Apr 3, 2015
    @Sinute
    好高端的写法。。。
    else没有花括号不能忍。。
    0x000
        18
    0x000  
       Apr 3, 2015
    array_unique(array_merage(array_column($arr, 'period'), array_column($arr, 'price')));

    或者使用array_map,或者使用傻瓜式循环
    kmvan
        19
    kmvan  
       Apr 3, 2015
    我漏了一个地方
    if(isset($new[$v['period']])){
    改成
    if(isset($new[$v['period'] . $v['price']])){
    msg7086
        20
    msg7086  
       Apr 3, 2015
    @kmvan 最好把key单独赋值,不容易出错。

    https://gist.github.com/msg7086/01761d72e1d8c2cf12ae
    About     Help     Advertise     Blog     API     FAQ     Solana     910 Online   Highest 6679       Select Language
    创意工作者们的社区
    World is powered by solitude
    VERSION: 3.9.8.5 44ms UTC 22:43 PVG 06:43 LAX 15:43 JFK 18:43
    Do have faith in what you're doing.
    ubao msn snddm index pchome yahoo rakuten mypaper meadowduck bidyahoo youbao zxmzxm asda bnvcg cvbfg dfscv mmhjk xxddc yybgb zznbn ccubao uaitu acv GXCV ET GDG YH FG BCVB FJFH CBRE CBC GDG ET54 WRWR RWER WREW WRWER RWER SDG EW SF DSFSF fbbs ubao fhd dfg ewr dg df ewwr ewwr et ruyut utut dfg fgd gdfgt etg dfgt dfgd ert4 gd fgg wr 235 wer3 we vsdf sdf gdf ert xcv sdf rwer hfd dfg cvb rwf afb dfh jgh bmn lgh rty gfds cxv xcv xcs vdas fdf fgd cv sdf tert sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf sdf shasha9178 shasha9178 shasha9178 shasha9178 shasha9178 liflif2 liflif2 liflif2 liflif2 liflif2 liblib3 liblib3 liblib3 liblib3 liblib3 zhazha444 zhazha444 zhazha444 zhazha444 zhazha444 dende5 dende denden denden2 denden21 fenfen9 fenf619 fen619 fenfe9 fe619 sdf sdf sdf sdf sdf zhazh90 zhazh0 zhaa50 zha90 zh590 zho zhoz zhozh zhozho zhozho2 lislis lls95 lili95 lils5 liss9 sdf0ty987 sdft876 sdft9876 sdf09876 sd0t9876 sdf0ty98 sdf0976 sdf0ty986 sdf0ty96 sdf0t76 sdf0876 df0ty98 sf0t876 sd0ty76 sdy76 sdf76 sdf0t76 sdf0ty9 sdf0ty98 sdf0ty987 sdf0ty98 sdf6676 sdf876 sd876 sd876 sdf6 sdf6 sdf9876 sdf0t sdf06 sdf0ty9776 sdf0ty9776 sdf0ty76 sdf8876 sdf0t sd6 sdf06 s688876 sd688 sdf86