请教一个 py2 和 py3 的转换问题 。

#coding=utf8 import base64 import struct from random import seed from random import randint from hashlib import md5 import codecs seed(1) op = 0xffffffff delta = 0x9e3779b9 value = b'\x00\x80\xe8\xdec\xd5{\xe0\x1b6\x8f\x97\xbf\xc2F\xb4\x0b\xe1\xa5\xc7\x84h33M\xc2\x18\xc7Y\xb2B\\\xa3\xf8\x9dFH^-p\x07\x13\xa3\xd1\xe8\xb5\xe2\xe8\x82\xb9\xe1\xab\x15\xf1I\xcf\xd6\x98\xb7\x02\xe4\x82\xc8\xb2N\x95\xd4\x03b\x1dF@\\\xf5\xaez/\xc0-\xcaOA\x84\x19\x93l\xf0"\x0b\'\x8f\x1f\xf7\xc9\x830\xa1\xc9\x98\x9d\xad\xd8\x07\x0b\xcdS\x9c\x13[\xddxK\x91\xa4J\xb5\x9b`0%\xccd\xd4\x98\xed\xa4xc)\t\x00\x00\x00\x00D\x87\xe9\xe9\x00\x04WUWV' key = b")7\xf7:!\xb7\xdetp0'\xf5\xd8\xfaK\x82" def xor(a, b): a1,a2 = struct.unpack('>LL', a[0:8]) b1,b2 = struct.unpack('>LL', b[0:8]) r = struct.pack('>LL', ( a1 ^ b1) & op, ( a2 ^ b2) & op) return r def code(v, k): n=16 k = struct.unpack('>LLLL', k[0:16]) y, z = struct.unpack('>LL', v[0:8]) s = 0 for i in range(n): s += delta y += (op &(z<<4))+ k[0] ^ z+ s ^ (op&(z>>5)) + k[1] y &= op z += (op &(y<<4))+ k[2] ^ y+ s ^ (op&(y>>5)) + k[3] z &= op r = struct.pack('>LL',y,z) return r def encrypt(v, k): END_CHAR = b'\0' fills = b'' filln = ((8-(len(v)+2))%8) + 2 for i in range(filln): fills = fills + chr(randint(0,0xff)) v = (chr((filln - 2)|0xF8) + fills + v + END_CHAR *7) tr = to = o = END_CHAR * 8 r = b'' for i in range(0, len(v), 8): g = v[i:i+8] o = xor(g,tr) tr = xor(code(o,k),to) to = o r += tr return r print( base64.b64encode(encrypt(value,key)).replace('/', '-').replace('+', '*').replace('=', '_') )