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使用 Python 中 SocketServer 模块中的 ForkingMixIn 处理客户端请求，实现给客户端发送 PID 和时间功能
class ForkingServerHandler (SocketServer.BaseRequestHandler ):
def handle (self ):
data = self.request.recv (1024 )
current_pid = os.getpid ()
respOnse= 'server pid: %s server time %s:' % (current_pid, server_time ())
print response
self.request.send (response )
return
class ForkingServer (SocketServer.TCPServer, SocketServer.ForkingMixIn,):
"""time server , return the server time to client"""
pass
但发现在本地开启了好几个客户端后服务端仍然只使用一个进程处理请求，为何？
class ForkingServerHandler (SocketServer.BaseRequestHandler ):
def handle (self ):
data = self.request.recv (1024 )
current_pid = os.getpid ()
respOnse= 'server pid: %s server time %s:' % (current_pid, server_time ())
print response
self.request.send (response )
return
class ForkingServer (SocketServer.TCPServer, SocketServer.ForkingMixIn,):
"""time server , return the server time to client"""
pass
但发现在本地开启了好几个客户端后服务端仍然只使用一个进程处理请求，为何？
 | 1 paw Aug 26, 2015 class ForkingServer (SocketServer.TCPServer, SocketServer.ForkingMixIn,): 改成 class ForkingServer (SocketServer.ForkingMixIn, SocketServer.TCPServer ): 继承循序的问题 |
| 2 paw Aug 26, 2015 PS ：不推荐用自带库的这个 forkinng ，还不如下面来的方便 s = SocketServer.TCPServer (('', PORT ),HandlerClass ) for x in xrange (fork_process ): pos = x pid = os.fork () if pid == 0 : break s.serve_forever () PPS:学 python 网络，先把标准库的 SocketServer.py 读了，你的问题就在这文件的 614 行（ python 2.7.9 ） |
 | 3 ivito OP @paw 非常感谢，解释完全正确，是继承顺序的问题。 SocketServer.py 写的确实很赞，几百行实现了一个服务器框架。 |
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