求解答，关于 JS 中正则量词的贪婪模式和惰性模式的问题？ - V2EX
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zhzhzxh

求解答，关于 JS 中正则量词的贪婪模式和惰性模式的问题？

  •   
  •   zhzhzxh Oct 28, 2015 2622 views
    This topic created in 3834 days ago, the information mentioned may be changed or developed.
    哪位大神可以解释一下为什么'abcdef'.replace(/[a-z]+/,'1');的结果是‘ 1 ’而不是‘ 111111 ’呢？
  • 量词
  • Replace
  • a-z
  • abcdef
    4 replies    2015-10-29 07:02:17 +08:00
    jings
        1
    jings  
       Oct 28, 2015 via Android
    加好代表一个或一个以上 replace 左边匹配 abcdef 替换成 右边 1 就为 1
    去掉加号和换成？号 分别测试下
    BOYPT
        2
    BOYPT  
       Oct 28, 2015   1
    'abcdef'.replace(/[a-z]/g,'1');
    "111111"
    jonnyhsy
        3
    jonnyhsy  
       Oct 29, 2015
    'abcdef'.replace(/[a-z]+?/,'1');
    "1bcdef"

    "?" 加在重复匹配符(+/./?)表示非贪婪，默认贪婪匹配，所以你的正则吃掉了所有的"abcde", 替换成了 1
    SoloCompany
        4
    SoloCompany  
       Oct 29, 2015
    'abcdef'.replace(/[a-z]+?/g,'1 ’);
    111111
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