python2 如何正确的处理 4 字节的字符,为什么一个字符变成了两个? - V2EX
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zeroten

python2 如何正确的处理 4 字节的字符,为什么一个字符变成了两个?

  •  
  •   zeroten
    ladder1984 Jan 21, 2016 3349 views
    This topic created in 3748 days ago, the information mentioned may be changed or developed.
    x = u'\U0001f604abc' print('length:',len(x)) for i in x: print(i) 

    得到输出:

    ('length:', 5)


    a
    b
    c

    x 是 4 个字符,其中第一个是 4 字节字符,一个笑脸表情的 unicdoe 码,现在显然被拆分成了两个。我写的过滤函数就过滤失败了:

    def filter_invalid_str(text):
    return ''.join(map(lambda x: x if u'\u0000' < x < u'\uFFFF' else '_', text))

    所以,明明一个字符为什么变成了两个,如何当作一个字符处理?

    8 replies    2016-01-21 20:07:16 +08:00
    Zzzzzzzzz
        1
    Zzzzzzzzz  
       Jan 21, 2016
    编译 python2 的时候加上--enable-unicode=ucs4
    Hackathon
        2
    Hackathon  
       Jan 21, 2016
    zeroten
        3
    zeroten  
    OP
       Jan 21, 2016
    或者,过滤掉 u'\u0000' < x < u'\uFFFF'之外的字符有什么好的实现方法?
    zeroten
        4
    zeroten  
    OP
       Jan 21, 2016
    @Zzzzzzzzz 这个编译是指?编译 python 的 C 源码么?
    Zzzzzzzzz
        7
    Zzzzzzzzz  
    &bsp;  Jan 21, 2016
    @zeroten 对, 你现在是 ucs2.
    zeroten
        8
    zeroten  
    OP
       Jan 21, 2016
    @Hackathon
    @Zzzzzzzzz

    很好奇为什么落在[\uD800-\uDBFF][\uDC00-\uDFFF]这个范围内
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