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有下面一段代码，分别打印 1 1 2 3 5 和 0 0 0 0 0，请问后面一个迭代器为什么不会打印 0 1 2 3 4 ？
class Fib(object): def __init_(self): self.prev = 0 self.curr = 1 def next(self): value = self.curr self.curr += self.prev self.prev = value return value def __iter__(self): return self class T(object): def __iter__(self): return self def next(self): for i in range(5): return i f = Fib() t = T() print next(f) print next(f) print next(f) print next(f) print next(f) print next(t) print next(t) print next(t) print next(t) print next(t) Supplement 1 Feb 17, 2018
已结，大半夜大脑短路问了这么个问题。
 | 1 quinoa42 Feb 17, 2018 因为已经 return 了，后面 i=1,2,3,4 根本不会运行 |
 | 2 wwqgtxx Feb 17, 2018 via iPhone yield 才是给迭代器用的 |
 | 3 KKKKKK Feb 17, 2018 via Android 查一查 magic method Next 调用的是 __next__ 这个方法 |
 | 4 lrxiao Feb 17, 2018 generator_instance.gi_frame.f_locals |
 | 8 ch3nOr Feb 17, 2018 #1 说的对，每次你用 next(t) 的候，就用一次 t.next()。你可以在[]( http://pythontutor.com/visualize.html) 下你的代，可化你的行步。 |
 | 9 wallriding Feb 17, 2018 for i in range(5): return i 楼主你再看看？ |
| 10 ch3nOr Feb 17, 2018 Fib 的，了前迭代的，所以完全 |
 | 11 flowarmor OP @wallriding 嗯哼，昨夜太困大脑短路了。 |
 | 12 frostming Feb 23, 2018 |