
1 undertonememorie Jun 7, 2018 var001 = ‘’ var002 = ‘’ var003 = ‘’ |
2 undertonememorie Jun 7, 2018 var001 = ‘’ var002 = ‘’ var003 = ‘’ try: var001 = func001(args) |
3 vicalloy Jun 7, 2018 应当就一个 for 循环的吧 for v in [1, 2, 3, 4, 5]: ....pass |
4 newbieo0O Jun 7, 2018 跑一遍 fun 后解构赋值? |
5 clino Jun 7, 2018 via Android 弄个函数数组,来一个 for 循环,结果也 append 到一个数组里 |
6 vicalloy Jun 7, 2018 抱歉,看错了,应当函数不同。 def ignore_exception(func, *args, **kwargs): ....func(*args, **kwargs) for f in [func1, func2, func2]: ....ignore_exception(f, arg1) |
7 MicroCatPad Jun 7, 2018 可以用装饰器 |
8 CosimoZi Jun 7, 2018 反射了解一下 |