请教个python替换字符的问题 - V2EX
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gino
V2EX    Python

请教个python替换字符的问题

  •  
  •   gino 2012-11-20 15:03:15 +08:00 3802 次点击
    这是一个创建于 4778 天前的主题,其中的信息可能已经有所发展或是发生改变。
    _re_imgs = re.compile('(http[s]?://?\S*\w\.(jpg|jpe|jpeg|gif|png))\w*', re.UNICODE|re.I|re.M|re.S)
    _re_gist = re.compile('(http[s]?://gist.github.com/[\d]+)', re.UNICODE|re.I|re.M|re.S)
    _re_con_sup = re.compile('\B!([^<>\/].+?)!\B', re.UNICODE|re.I|re.M|re.S)

    #sup
    if _re_con_sup.search(text):
    text = _re_con_sup.sub(r'<div id="sup">\1</div>', text)
    #gist
    if '://gist' in text:
    text = _re_gist.sub(r'<script src="\1.js"></script>',text)
    #auto img
    if _re_imgs.search(text):
    text = _re_imgs.sub(r'<a class="imga" href="\1"><img class="lazy" border="0" style="max-width:540px;" src="./static/grey2.gif" data-original="\1"/></a>', text)

    怎么对_re_con_sup过的内容就不做_re_imgs、_re_gist处理了呢,谢谢
    第 1 条附言    2012-11-22 13:44:22 +08:00
    已经搞定了,谢谢了
    3 条回复    1970-01-01 08:00:00 +08:00
    dreampuf
        1
    dreampuf  
       2012-11-20 19:29:55 +08:00   1
    1. 合并到一个regex中,用"|"处理.
    2. 获取所有_re_con_sup匹配的边界,在后面的捕获中一旦在这些边界中的,就视为匹配不成功。
    gino
        2
    gino  
    OP
       2012-11-20 23:01:20 +08:00
    @dreampuf
    第一个方式,我测试过了,因为regex比较多,会很麻烦
    对应第二个方式,是否能在指点下,感谢了
    dreampuf
        3
    dreampuf  
       2012-11-21 00:48:09 +08:00
    @gino
    In [1]: import re

    In [2]: a = re.search(r"""(?:(?P<pic>http[s]?://?\S*\w\.(jpg|jpe|jpeg|gif|png))\w*|(?P<gist>http[s]?://gist.github.com/[\d]+)|\B!(?P<con>[^<>\/].+?)!\B)""", "http://huangx.in/a.jpg")

    In [3]: a.groupdict()
    Out[3]: {'con': None, 'gist': None, 'pic': 'http://huangx.in/a.jpg'}
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