关于 apscheduler 定时任务框架,终止线程的方法 - V2EX
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tanwill12138

关于 apscheduler 定时任务框架,终止线程的方法

  •  
  •   tanwill12138 Apr 20, 2020 3893 views
    This topic created in 2212 days ago, the information mentioned may be changed or developed.

    代码如下:

    def scheduler_run(self, datas1, datas2, inputpath): self.scheduler = BlockingScheduler() self.scheduler.add_job(self.main, 'interval', secOnds=1, id='test_01', args=(datas1, datas2, inputpath)) if HtmlMain.count < 10: self.scheduler.start() else: self.scheduler.shutdown() 

    目前我的需求是:以某个变量为条件,使得终止该定时任务

    可能我方向错误了,还望前辈不吝赐教。 或者有更好的方法,我也愿意去了解。

    7 replies    2020-04-27 14:28:55 +08:00
    Harlaus
        1
    Harlaus  
       Apr 20, 2020
    interval 换成 corn,
    HtmlMain.count 在 self.main 里定义,用 while break 控制终止
    tanwill12138
        2
    tanwill12138  
    OP
       Apr 20, 2020
    @Harlaus 你好,我刚刚尝试了,实际上 scheduler 还在运行,只是没有在执行下一步程序
    cian
        3
    cian  
       Apr 20, 2020
    建议用 celery
    tanwill12138
        4
    tanwill12138  
    OP
       Apr 21, 2020
    @cian 好吧,我转 celery 了,请问其中坑多吗?
    cian
        5
    cian  
       Apr 21, 2020
    还好吧 。如果访问第三方接口,一定要设置超时时间,这个算是小贴士
    wenqiang1208
        6
    wenqiang1208  
       Apr 21, 2020
    有类似需求 直接用 celery 了
    sujin190
        7
    sujin190  
       Apr 27, 2020
    https://segmentfault.com/a/1190000022085297

    专门的定时任务管理服务显然更方便啊
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