
private boolean isOdd ( int i );
不限正数和负数啊
求大佬指教
1 mightofcode Apr 27, 2020 return Math.abs(i)%2==1; |
2 jzmws Apr 27, 2020 i % 2==0 |
4 shucc Apr 27, 2020 return (num & 1) == 1; |
5 crayygy Apr 27, 2020 via iPhone 看二进制的最后一位 |
9 luxinfl OP |
10 yukiloh Apr 27, 2020 via Android 位判断的亮了 |
11 hunter2015 Apr 27, 2020 我似乎只能说,NB |
12 luxinfl OP 这就叫差距啊 |
13 zllmath Apr 27, 2020 |
14 ericls Apr 27, 2020 via iPhone 编译器说: 你以为你很聪明? |
16 cloudfstrife Apr 27, 2020 via Android @shucc 这个就叫专业 |