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a = [1, 2, 3] b = [a for i in range(1000)] c = [b for i in range(1000)] 现在想从 c 取每个 int （每个 1 、2 、3 ），然后构成一个 3x1000x1000 的 numpy matrix 求问大佬们有什么除了遍历以外更快的方法。 感激不尽！
 | 1 chizuo Apr 29, 2020 为什么要取呢？ 直接 x = np.asarray(c) 不就行了？ |
 | 2 BaseVariable OP @chizuo 对啊。。是我想错了 |
 | 3 necomancer May 8, 2020 c = np.empty((1000,1000,3)) c[...,:]=a c = np.transpose(c, (2,0,1)) |
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