Python 排列组合生成

老哥们, 请教一个问题, 是关于排列组合的, 前几天和老哥们讨论了一下, 能是能解决, 但感觉不太方便 看一个简单的例子应该就明白了.

<school type="primary|middle|university"> <class number="1"/> </school> 

to

<school type="primary"> <class number="1"/> </school> <school type="middle"> <class number="1"/> </school> <school type="university"> <class number="1"/> </school> 

目前是我这样做的, 用了一个模版 template

<school type="{school_type}"> <class number="{class_number}"/> </school> 

代码和上面的学校例子有点不同，因为我的完整需求是这样的

<!-- base --> <cross> <rule1 hint="rule 1" name="long" val1="30|60" val2="90|120" cOndition="1"> <necessary_rule val1="60" val2="120" cOndition="1"/> </rule1> </cross> <!-- generator --> <!-- 1 --> <cross> <rule1 hint="rule 1" name="long" val1="30" val2="90" cOndition="1"> <necessary_rule val1="60" val2="120" cOndition="1"/> </rule1> </cross> <!-- 2 --> <cross> <rule1 hint="rule 1" name="long" val1="30" val2="120" cOndition="1"> <necessary_rule val1="60" val2="120" cOndition="1"/> </rule1> </cross> <!-- 3 --> <cross> <rule1 hint="rule 1" name="long" val1="60" val2="90" cOndition="1"> <necessary_rule val1="60" val2="120" cOndition="1"/> </rule1> </cross> <!-- 4 --> <cross> <rule1 hint="rule 1" name="long" val1="60" val2="120" cOndition="1"> <necessary_rule val1="60" val2="120" cOndition="1"/> </rule1> </cross> 

代码

import xml.etree.ElementTree as ET import itertools from typing import Dict, Optional def producer(rule, root_tag: Optional[str] = ''): rule_tag = rule.tag rule_temp = {} rule_attrib = rule.attrib for k, v in rule_attrib.items(): k = f'{root_tag}{rule_tag}_{k}' if 'val' in v: v = rule_attrib.get(v) rule_temp[k] = v.split('|') return rule_temp def params_parser(): tree = ET.parse('rule.xml') rule_params = {} root = tree.getroot() for strategy in root: for rule in strategy: rule_params.update(**producer(rule)) for child_rule in rule: rule_params.update(**producer(child_rule, root_tag=f'{rule.tag}_')) return rule_params def rule_generator(rule_params: Dict): with open('rule_template.xml', encoding='utf-8') as f: template = f.read() for values in itertools.product(*rule_params.values()): params = dict(zip(rule_params.keys(), values)) data = template.format(**params) print(data) def main(): rule_params = params_parser() rule_generator(rule_params) if __name__ == '__main__': main() 

我的思路是取出所有 tag 的 attrib，然后替换到模版. 上面的做法能解决我的问题，但这样每次都要弄一个模版我觉得很麻烦，有没有更简洁的办法