有没有现成的代码分析出数组的通项公式? - V2EX
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有没有现成的代码分析出数组的通项公式?
tuding
Nov 12, 2021
2833 views
This topic created in 1640 days ago, the information mentioned may be changed or developed.
假设我有一个有序的、含有 n 个数的数组,有没有现成的代码或者程序可以分析出这个数组的数字规律(即通项公式),以此来估计第 n+1 个数大概是多少?
如果没有现成的话,应该怎么设计算法,才能让通项公式尽可能的精确呢?
(假设这个数组是有规律的)
数组
现成
公式
个数
10 replies
2021-11-13 10:45:53 +08:00
1
murmur
Nov 12, 2021
这不就是万能的多项式拟合么,只要系数够离谱下一项就是 114514
2
pkumsy
Nov 12, 2021
1
有一个网站,不过只限于整数数列
https://oeis.org/
基本上收录了你能想到、想不到的数组
可以看一下有没有参考价值
3
dbsquirrel
Nov 12, 2021 via iPhone
4
MengQuadra
Nov 12, 2021
直接查 OEIS 吧, 代码分析我估计没有可行性
5
KaronV
Nov 12, 2021
单就多项式拟合,N 个数,用 N+1 次多项式可以拟合出任意一个特定的 N+1 项
没什么实际意义
6
Building
Nov 12, 2021 via iPhone
高端版: AI 算法
低端版: 推荐算法
7
2TsukasA
Nov 12, 2021
拉格朗日插值,不仅你的下一项可以是 114514 ,甚至你的下下一项可以是 1919810
8
nightwitch
Nov 12, 2021
1
翻数值分析插值和拟合那一章就懂了。有无数组解,没啥意义。
9
aguesuka
Nov 12, 2021
wolfram alpha
10
uni
Nov 13, 2021
从 n 个数中可以推出无数个通项公式。。。
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