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Python 每日一练 => 等分字符串
import re # 'F0-B4-29-98-CE-34' '-'.join(re.findall(r'.{2}', 'F0B42998CE34')) 使用场景：字符串平均切割、MAC 地址切割等操作。
 | 1 krixaar 2022-08-12 11:39:28 +08:00  13 from textwrap import wrap # 'F0-B4-29-98-CE-34' '-'.join(wrap('F0B42998CE34', 2)) |
 | 3 wang9571 2022-08-12 11:50:59 +08:00  2 '-'.join(s[x:x+2] for x in range(0, len(s), 2)) |
 | 5 piglei 2022-08-12 19:25:09 +08:00 好答案前面有了，我再多贡献一条基于正则的花活。若干年前学自《精通正则表达式》，对于当时的我过于震撼，牢记至今： >>> s = 'F0B42998CE34' >>> import re >>> re.sub(r'(?<=.)(?=(..)+$)', '-', s) 'F0-B4-29-98-CE-34' |
 | 6 luckyc 2022-08-13 19:22:35 +08:00 string='20220202' # out put-> 2022-02-02 楼下的请解答 |
 | 7 elboble 2022-08-13 22:50:18 +08:00 ''.join([(str[i]+('-' if i%2 and not (i==1 or i == len(str)-1) else '')) for i in range(len(str))]) |
 | 8 brucmao 2022-08-19 16:23:18 +08:00 ```python s = 'F0B42998CE34' def chunk(iterable, chunk_size, on_chunk=None): on_chunk = on_chunk or (lambda x:x) return [on_chunk(chunk) for chunk in zip(*[iter(iterable)] * chunk_size)] res = chunk(s,2,''.join) print('-'.join(res)) ``` https://github.com/lisonge/lisonge.gitHub.io/raw/main/1x1.png#YGBgcHl0aG9uCgpzID0gJ0YwQjQyOTk4Q0UzNCcKCmRlZiBjaHVuayhpdGVyYWJsZSwgY2h1bmtfc2l6ZSwgb25fY2h1bms9Tm9uZSk6CiAgICBvbl9jaHVuayA9IG9uX2NodW5rIG9yIChsYW1iZGEgeDp4KQogICAgcmV0dXJuIFtvbl9jaHVuayhjaHVuaykgZm9yIGNodW5rIGluIHppcCgqW2l0ZXIoaXRlcmFibGUpXSAqIGNodW5rX3NpemUpXQoKcmVzID0gY2h1bmsocywyLCcnLmpvaW4pCnByaW50KCctJy5qb2luKHJlcykpCgoKCmBgYA== |
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