requests 线程池无法中止子线程问题 - V2EX
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evemoo
V2EX    Python

requests 线程池无法中止子线程问题

  •  
  •   evemoo 2023-08-08 11:35:02 +08:00 1924 次点击
    这是一个创建于 864 天前的主题,其中的信息可能已经有所发展或是发生改变。

    后面会接触断点续传、aiohttp 、httpx (

    线程池提交完任务(哪怕只开了一个 worker ),tqdm 显示进度条后按 Ctrl + C 并不会中断正在下载的任务。

    from concurrent.futures import ThreadPoolExecutor, as_completed import requests from tqdm import tqdm def download(url): try: filesize = int(requests.get(url, stream=True).headers['Content-length']) or 0 filename = requests.get(url, stream=True).headers['content-disposition'] with requests.get(url, stream=True) as responese: with tqdm( total=filesize, desc=f"Downloading: ", unit="B", unit_divisor=1024, ascii=True, unit_scale=True, ) as bar: with open(filename, mode="ab") as f: # 追加模式 for chunk in responese.iter_content(1024): f.write(chunk) bar.update(len(chunk)) except (SystemExit, KeyboardInterrupt): raise "KeyboardInterrupt" urls = [...] with ThreadPoolExecutor(maxworkers=8) as pool: tasks = pool.map(download, urls) for task in as_completed(tasks): print(task.result()) 
    第 1 条附言    2023-08-08 12:27:31 +08:00

    更准确的提问应该是:concurrent.futures 的 submit、map 方法提交后,无法捕获 Ctrl + C 信号终止子线程 简单测试 delay server 如下:

    import time from fastapi import FastAPI from fastapi.responses import FileResponse from uvicorn import run app = FastAPI() @app.get("/") def hello(): return {"data": "hello world"} @app.get("/pic/{file}") def d(file: str): time.sleep(60) return FileResponse(f"pic/{file}") if __name__ == "__main__": run("download_server:app", host="localhost", port=8000, reload=True) 
    6 条回复    2023-08-11 10:54:01 +08:00
    t133
        1
    t133  
       2023-08-08 11:55:08 +08:00 via iPhone   1
    指定 daemon thread 可解
    evemoo
        2
    evemoo  
    OP
       2023-08-08 13:13:59 +08:00
    @t133
    实际测试,join() 还要带 timeout 参数才能 raise "KeyboardInterrupt"

    ```python
    tasks = []
    for url in urls:
    task = threading.Thread(target=download, args=(url,))
    task.setDaemon(True)
    tasks.append(task)
    task.start()

    for task in tasks:
    task.join(2)
    ```
    evemoo
        3
    evemoo  
    OP
       2023-08-08 13:15:00 +08:00
    搜了下 concurrent.futrues 的 daemon ,没有找到相似解法。
    ruanimal
        4
    ruanimal  
       2023-08-08 14:08:29 +08:00
    你需要的是 graceful shutdown 吧,看看 signal 处理
    ClericPy
        5
    ClericPy  
       2023-08-08 18:40:02 +08:00
    和 Requests 无关, 多线程本来就很难终止, 不然我也不会 all-in 协程去了.
    chaoshui
        6
    chaoshui  
       2023-08-11 10:54:01 +08:00   1
    如果不关心子线程的任务情况的话,可以直接在主线程关闭线程池 pool. shutdown(wait=False) 。
    如果关心子线程的任务情况,比如正在下载的文件继续下载完毕或者怎样,可以通过一个 threading.Event 通知正在进行的任务退出,配合 Future 对象的 cancel 方法可以干净地处理所有的任务。
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